Q. 3 A4.0( 2 Votes )
Evaluate each of
Answer :
Let cot–1() = y
⇒ cot y =
= – cot
= cot
= cot
The range of principal value of cot–1is (0, π)
and cot
∴ The principal value of cot–1() is
…(1)
Let,
cosec–1–2 = z
⇒ cosec z = –2
⇒ –cosec z = 2
⇒ –cosec = 2
As we know cosec(–θ) = –cosecθ
∴ –cosec = cosec
The range of principal value of cosec–1 is –{0} and
cosec = –2
Therefore, the principal value of cosec–1(–2) is …(2)
Let sec–1 = w
⇒ sec w =
= sec
The range of principal value of sec–1is [0, π]–{}
and sec
Therefore, the principal value of sec–1() is
…(3)
From (1), (2) and (3) we can write the above equation as
=
=
=
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