Q. 6 D5.0( 1 Vote )
Evaluate each of
The value of cot is √3.
∴ The question becomes cot–1(√3).
Let cot–1(√3) = y
⇒ cot y = √3
= cot = √3
The range of principal value of cot–1is (0, π)
and cot = √3
∴ The principal value of cot–1(cot) is .
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