Answer :

Given sin-1 (sin 1550°)


= sin-1 (sin (1440° + 110°))


= sin-1 (sin (360° × 4 + 110°))


We know that sin (2nπ + θ) = sin θ


= sin-1 (sin 110°)


We know that sin-1 (sin θ) = π – θ, if θ [π/2, 3π/2]


= 180° - 110°


= 70°


sin-1 (sin 1550°) = 70°


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