Q. 6 C5.0( 2 Votes )

# Evaluate each of the following:

Answer :

The value of cot is 1.

∴ The question becomes cot^{–1}(1).

Let cot^{–1}(1) = y

⇒ cot y = 1

= cot = 1

The range of principal value of cot^{–1}is (0, π)

and cot = 1

∴ The value of cot^{–1}(cot) is .

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