Answer :

We are given that,


Take,



We can write as,



Then,



Also, by trigonometric identity



[, lies in III Quadrant and tangent is positive in III Quadrant]



Using the property of inverse trigonometry, that is, tan-1(tan A) = A.



Now, take



We can write as,



Then,



By trigonometric identity,



[, lies in II Quadrant and tangent is negative in II Quadrant]




Using the property of inverse trigonometry, that is, tan-1(tan A) = A.



We have,



4α = π and 3β = π


Since, the values of 4α and 3β are same, that is,


4α = 3β = π


Therefore,


4α = 3β

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