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Answer :

Let tan–1() = y


tan y =


= – tan


= tan


The principal value of tan–1() is …(1)


Let cot–1() = z


cot z =


= – cot


= cot


= cot


The range of principal value of cot–1is (0, π)


and cot


The principal value of cot–1() is …(2)


sin = –1


tan–1(–1)


Let tan–1(–1) = w


tan w = –1


= – tan = 1


= tan


The principal value of tan–1(–1) is …(3)


From(1),(2) and (3) we get


=


=


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