Q. 3 B5.0( 2 Votes )

# Evaluate each of

Answer :

For finding the solution we first of need to find the principal value of

Sin–1 Let,

Sin–1 =y

sin y = sin The range of principal value of sin–1 is and sin Therefore, the principal value of Sin–1 is The above equation changes to cot–1(2cos )

Now we need to find the value of 2cos cos 2cos = 1 x 2cos = 1

Now the equation simplification to cot–1(1)

Let cot–1(1) = y

cot y = 1

= cot = 1

The range of principal value of cot–1is (0, π)

and cot = 1

The principal value of cot–1(2cos(Sin–1 )) is Rate this question :

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