Answer :

Given sin (π/3 – sin-1 (-1/2))


We know that sin-1 (-θ) = -sin-1 θ


= sin (π/3 + sin-1 (1/2) 0)


= sin (π/3 + π/6)


= sin (π/2)


= 1


sin (π/3 – sin-1 (-1/2)) = 1


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