Q. 205.0( 1 Vote )

Let A = R – {3}, B = R – {1}. Let f : A B be defined by x A . Then show that f is bijective.

Answer :

Given that,


In order to prove that f is one-one, it is sufficient to prove that f(x1)=f(x2) x1=x2 x1, x2 A .


Let f(x1)=f(x2)



(x1-2)(x2-3) = (x2-2)(x1-3)


x1x2-3x1-2x2+6 = x1x2-3x2-2x1+6


-3x1-2x2 = -3x2-2x1


-3x1+2x1 = -3x2+2x2


(-3+2) x1 = (-3+2)x2


x1 = x2


f is one-one.


f is onto if every element of B is the f-image of some element of A.


let f(x) = y



x-2 = y(x-3)


x-2 = xy-3y


x-xy = -3y+2


x(1-y) = -3y+2




Thus, for each y B there exists such that f(x) = y.


Hence, f is onto.


Since, f is one-one and onto therefore f is bijective.


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