We have,gof(x) = g(f(x))⇒ gof(x) = g(2x+1)= (2x+1)2 – 2= (4x2+1+4x) – 2= 4x2+4x-1∴ gof = 4x2+4x-1

Q. 33.6( 13 Votes )

Let f, g :R <span

Answer :

We have,

gof(x) = g(f(x))

⇒ gof(x) = g(2x+1)

= (2x+1)² – 2

= (4x²+1+4x) – 2

= 4x²+4x-1

∴ gof = 4x²+4x-1

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