Answer :

True

Given that, f :N A defined by f (2n–1) = 0, f (2n) = 1,n N,


We observe that for each element of A(co-domain) there exist a pre image in N(domain).


For 0 A there exist (2n-1), n N


For 1 A there exist (2n), n N


Thus, the mapping is onto.


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