Answer :

False

Let R be the relation defined on Z by mRn if m is a integral multiple of n.


Let mRm R


m is a integral multiple of m.


Which is true since m is integral multiple of itself.


Thus, R is reflexive.


Let mRn R


m is a integral multiple of n


m= zn z Z



Since,


n is not integral multiple of m.


nRm R


Thus, R is not symmetric.


Let mRn R and nRp R


m is a integral multiple of n and n is a integral multiple of p


m is a integral multiple of p


mRp R


Thus, R is transitive.


Hence, the given statement is false.


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