Answer :
Given that, A = [–1, 1]
Let f(x1) = f(x2)
⇒
⇒ 2x1 = 2x2
⇒ x1 = x2
⇒ f is one one
Now, let f(x) = y
⇒
⇒ 2y= x
⇒ for y=1 ∈ A we will have x = 2 ∉ A
⇒ f is not onto
Thus, f is one-one and not onto.
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