Answer :

Let R = {(x,y): x + 4y =10, x,y N } be a relation defined on N.


R = {(2,2),(6,1)}


Now,


R is not reflexive (1,1) R.


R is not symmetric (6,1) R but (1,5) R


R is not transitive


(x,y) R x+4y=10 and (y,z) R y+4z=10


x-16z = -30


(x,z) R


Thus, R is neither symmetric nor reflexive nor transitive.


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