Answer :
Let R = {(x,y): x + y =10, ∀ x,y ∈ N } be a relation defined on N.
R = {(1,9),(2,8),(3,7),(4,6),(5,5),(6,4),(7,3),(8,2),(9,1)}
Now,
R is not reflexive ∵ (2,2) ∉ R.
R is symmetric ∵ (3,7) ∈ R ⇒ (7,3) ∈ R
R is not transitive ∵ (1,9) ∈ R and (9,1) ∈ R but (1,1) ∉ R.
Thus, R is symmetric but not reflexive not transitive.
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