Q. 9

# Find the particul

It is given that (1 + e2x) dy + (1 + y2) ex dx = 0

On integrating both sides, we get,

------(1)

Let ex = t

e2x = t2

exdx = dt

Substituting the value in equation (1), we get,

tan-1 y + tan-1 t = C

tan-1 y + tan-1 (ex) = C -------(2)

Now, y =1 at x = 0

Therefore, equation (2) becomes:

tan-1 1 + tan-1 1 = C

Substituting in (2), we get,

tan-1 y + tan-1 (ex) =

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