# For each of the d

It is given that This is equation in the form of (where, p = -3cotx and Q = sin2x)

Now, I.F. = Thus, the solution of the given differential equation is given by the relation:

y(I.F.) =   y cosec3x = 2cosecx + C

y = y = -2sin2x + Csin3x--------------(1)

Now, it is given that y = 2 when x = Thus, we get,

2 = -2 + C

C = 4

Now, Substituting the value of C = 4 in (1), we get,

y = -2sin2x + 4sin3x

y = 4sin3x - 2sin2x

Therefore, the required general solution of the given differential equation is

y = 4sin3x - 2sin2x.

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