# In each of   Here, putting x = kx and y = ky  = k0.f(x,y)

Therefore, the given differential equation is homogeneous.   To solve it we make the substitution.

y = vx

Differentiating eq. with respect to x, we get        Integrating both sides, we get  Put 1 + v2 = t

2vdv = dt  log(t)

log(1 + v2) = -logx + logC ( From (i) eq.)   The required solution of the differential equation.

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