# In each of

Here, putting x = kx and y = ky

= k0f(x,y)

Therefore, the given differential equation is homogeneous.

To solve it we make the substitution.

x = vy

Differentiation eq. with respect to x, we get

Integrating both sides, we get

Put ev + v = t

(ev + 1)dv = dt

logt

log(ev + v)

log(ev + v) = - logy + logC ( From (i) eq.)

Multiply by y on both side, we get

yex/y + x = C

x + yex/y = C

The required solution of the differential equation.

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