# In each of the question verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation:y = ex + 1 : y′′ – y′ = 0

It is given that y = ex + 1

Now, differentiating both sides w.r.t. x, we get,

Now, Again, differentiating both sides w.r.t. x, we get,

y” = ex

Now, Substituting the values of y’ and y” in the given differential equations, we get,

y” – y’ = ex - ex = RHS.

Therefore, the given function is the solution of the corresponding differential equation.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Interactive Quiz on DIfferential Calculus50 mins
Interactive Quiz on Differential Calculus | Check Yourself56 mins
Functional Equations - JEE with ease48 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses