At any point (x,

_{We know that (x,y) is the point of contact of curve and its tangent.}

slope(m1)for line joining (x,y) and (-4,-3) is

Also we know that slope of tangent of a curve is .

Now, according to the question,

(m2) = 2(m1)

Separating variables,

Integrating both sides,

⇒ log(y + 3) = 2log(x + 4) + log c

Now, this equation passes thorough the point (-2,1).

⇒ 4 = 4c

⇒ c = 1

Substitute the value of c in iii)