# At any point (x,

We know that (x,y) is the point of contact of curve and its tangent.

slope(m1)for line joining (x,y) and (-4,-3) is Also we know that slope of tangent of a curve is . Now, according to the question,

(m2) = 2(m1) Separating variables, Integrating both sides, log(y + 3) = 2log(x + 4) + log c  Now, this equation passes thorough the point (-2,1). 4 = 4c

c = 1

Substitute the value of c in iii) Rate this question :

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