Answer :

We know that (x,y) is the point of contact of curve and its tangent.


slope(m1)for line joining (x,y) and (-4,-3) is


Also we know that slope of tangent of a curve is .



Now, according to the question,


(m2) = 2(m1)



Separating variables,



Integrating both sides,



log(y + 3) = 2log(x + 4) + log c




Now, this equation passes thorough the point (-2,1).



4 = 4c


c = 1


Substitute the value of c in iii)



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