We know that (x,y) is the point of contact of curve and its tangent.
slope(m1)for line joining (x,y) and (-4,-3) is
Also we know that slope of tangent of a curve is .
Now, according to the question,
(m2) = 2(m1)
Integrating both sides,
⇒ log(y + 3) = 2log(x + 4) + log c
Now, this equation passes thorough the point (-2,1).
⇒ 4 = 4c
⇒ c = 1
Substitute the value of c in iii)
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