Q. 545.0( 1 Vote )

State whether the

Answer :

We have equation of line

…(i)


Equation of line passing through the origin and perpendicular to the given line


…(ii)


Now, the foot of perpendicular from origin on the line (i) is the point of intersection of lines (i) and (ii).


So, to find its locus we have to eliminate the variable a and b.


Squaring and adding eq. (i) and (ii), we get








x2 + y2 = c2


Hence, the given statement is TRUE


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