We have equation of line
Equation of line passing through the origin and perpendicular to the given line
Now, the foot of perpendicular from origin on the line (i) is the point of intersection of lines (i) and (ii).
So, to find its locus we have to eliminate the variable a and b.
Squaring and adding eq. (i) and (ii), we get
⇒ x2 + y2 = c2
Hence, the given statement is TRUE
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The equation of tRD Sharma - Mathematics