# The equation of t

Given that straight line passing through the point (3, 2)

and perpendicular to the line y = x

Let the equation of line ‘L’ is

y – y1 = m(x – x1)

Since, L is passing through the point (3, 2)

y – 2 = m(x – 3) …(i)

Now, given eq. is y = x

Since, the above equation is in y = mx + b form

So, the slope of this equation is 1

It is also given that line L and y = x are perpendicular to each other.

We know that, when two lines are perpendicular, then

m1 × m2 = -1

m × 1 = -1

m = -1

Putting the value of m in eq. (i), we get

y – 2 = (-1)(x – 3)

y – 2 = -x + 3

x + y = 3 + 2

x + y = 5

Hence, the correct option is (b)

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