Answer :
Given equation is
Since, p is the length of perpendicular drawn from the origin to the given line
Squaring both the sides, we have
…(i)
Since, a2, b2 and p2 are in AP
∴ 2p2 = a2 + b2
…(ii)
Form eq. (i) and (ii), we get
⇒ (a2 + b2)(a2 + b2) = 2(a2b2)
⇒ a4 + b4 + a2b2 + a2b2 = 2a2b2
⇒ a4 + b4 = 0
Hence Proved
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