Q. 85.0( 2 Votes )

Find the equation

Answer :

Given lines are:

2x + y = 5 …(i)


x + 3y = -8 …(ii)


Firstly, we find the point of intersection of eq. (i) and (ii)


Multiply the eq. (ii) by 2, we get


2x + 6y = -16 …(iii)


On subtracting eq. (iii) from (i), we get


2x + y – 2x – 6y = 5 – (-16)


-5y = 5 + 16


-5y = 21



Putting the value of y in eq. (i), we get





10x = 46



Hence, the point of intersection is


Now, we find the slope of the given equation 3x + 4y = 7


We know that the slope of an equation is




So, the slope of a line which is parallel to this line is also


Then the equation of the line passing through the point having slope is:


y – y1 = m (x – x1)







3x + 4y + 3 = 0


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