Q. 205.0( 1 Vote )

# P1, P<

Answer :

Given lines are y - √3|x| = 2

If x ≥ 0, then

y - √3x = 2 …(i)

If x < 0, then

y + √3x = 2 …(ii)

On adding eq. (i) and (ii), we get

y - √3x + y + √3x = 2 + 2

2y = 4

y = 2

Putting the value of y = 2 in eq. (ii), we get

2 + √3x = 2

√3x = 2 – 2

x = 0

Point of intersection of given lines is (0, 2)

Now, we find the slopes of given lines.

Slope of eq. (i) is

y = √3x + 2

Comparing the above equation with y = mx + b, we get

m = √3

and we know that, m = tan θ

tan θ = √3

θ = 60° [ tan 60° = √3]

Slope of eq. (ii) is

y = - √3x + 2

Comparing the above equation with y = mx + b, we get

m = -√3

and we know that, m = tan θ

tan θ = -√3

θ = (180° - 60°)

θ = 120° In ΔACB,  [given: AC = 5units] OB = OA + AB Hence, the coordinates of the foot of perpendicular = Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

Find the values oRD Sharma - Mathematics

The vertices of aRD Sharma - Mathematics

For specifying a Mathematics - Exemplar

If the line <spanMathematics - Exemplar

Equations of diagMathematics - Exemplar

If the coordinateMathematics - Exemplar