Q. 734.2( 5 Votes )
An organic compound A (molecular formula C2H4O2) reacts with Na metal to form a compound B and evolves a gas which burns with a pop sound. Compound A on treatment with an alcohol C in the presence of a little of concentrated sulphuric acid forms a sweet-smelling compound D (molecular formula C3H6O2). Compound D on treatment with NaOH solution gives back B and C. Identify A, B, C and D.
Answer :
A is ethanoic acid (CH3COOH) ; B is sodium ethanoate (CH3COONa); C is methanol (CH3OH) and D is methyl ethanoate (CH3COOCH3).
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PREVIOUSAn organic compound A having the molecular formula C3H8O is a liquid at room temperature. The organic liquid A reacts with sodium metal to evolve a gas which bums causing a little explosion. When the organic liquid A is heated with concentrated sulphuric acid at 170 �C, it forms a compound B which decolourises bromine water. The compound B adds on one molecule of hydrogen in the presence of Ni as catalyst to form compound C which gives substitution reactions with chlorine.
(a) What is compound A?
(b) What is compound B?
(c) What type of reaction occurs when A is converted into B?
(d) What is compound C?
(e) What type of reaction takes place when B is converted into C?NEXTWhich of the following hydrocarbons can decolourise bromine water and which cannot? Why?
C6H12, C6H14, C6H10
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