26 26 26 C 27 28 A 28 B 28 C 29 A 29 B 29 C 30 A 30 B 30 C 31 A 31 B 31 C 32 A 32 B 32 C 33 A 33 B 33 C 34 A 34 B 34 C 35 A 35 B 35 C 36 A 36 B 36 C 37 A 37 B 37 C

Lakhmir Singh & Manjit Kaur - Chemistry

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Q. 33 B4.5( 2 Votes )

Write the molecular formula of the third member of the homologues series of carbon compounds with general formula C_nH_2n+1OH.

Class 10th Lakhmir Singh & Manjit Kaur - Chemistry 4. Carbon and Its Compounds

Answer :

The general formula of homologous series of alcohol is C_nH_2n+1 -OH. Here, n is the number of carbon atoms in alcohol molecule.

If number of carbon atom (n)=3

Then, C₃H_2X3+1 OH= C₃H₇OH

Thus, the molecular formula of the third member of the homologues series of alcohol is C₃H₇OH. The IUPAC name of C₃H₇OH is propanol.

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PREVIOUSDefine a homologues series. Give the name and structural formula of one homologues of the following: CH3OH NEXTName any two fossil fuels.

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