Answer :

The capacitor C = 30 μF = 30 × 10 ^{-6} F

Inductor L = 27 mH = 27 × 10^{-3} H

The diagram is given :

Angular frequency ω_{r} is given by the following:

ω_{r} = 1/√ LC

ω_{r} = 1/{√(27 × 10^{-3}H × 30 × 10^{-6}F)}

on calculating, we get

ω_{r} = 1.11 × 10^{3} rad/s

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Expertsview all courses

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation

RELATED QUESTIONS :

The teachers of GPhysics - Board Papers

A. Draw a labeledPhysics - Board Papers

(a) In a series LPhysics - Board Papers

If a LC circuit iPhysics - Exemplar

If a LC circuit iPhysics - Exemplar

Electrical energyPhysics - Exemplar

Answer the followNCERT - Physics Part-I