Q. 213.7( 9 Votes )

Obtain the resona

Answer :

Given: L = 3.0 H

C = 27 μF,

In Farad, capacitance C = 27 × 10-6F

R = 7.4Ω

Angular frequency is given by the relation:

ωR = 1/√LC

ωR = 1(√27 × 10-6F × 3 H)

On calculating, we get

ωR = 111.11 rad/s

Q factor can be calculated as follows:

Q = ωRL/R

Q = (111.11(rad/s) × 3H)/7.4(Ω)

Q = 45.0446

The sharpness of the resonance of the circuit by reducing its ‘full width at half maximum’ by a factor of 2 by reducing R to half.

i.e. R = R/2 = 7.4(Ω)/2 = 3.7Ω

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