# A. Draw a labeled

A)

The schematic diagram of an AC generator is shown in the above figure. This is an electrical machine which converts mechanical energy into useful electrical energy. AC generator consists of a coil mounted on a rotor shaft. The rotational axis of the coil is kept at 900 to the direction of the magnetic field. The coil (called armature) is mechanically rotated in the uniform magnetic field which can be produced by permanent magnets or electromagnets. The rotation of the coil causes the magnetic flux through it to change, so as per Faraday’s law of electromagnetic induction, an emf is induced in the coil. To connect the coil to the external circuit its ends are connected by slip rings and brushes.

When the coil is rotated with a constant angular speed ω, the angle between the magnetic field vector B and the area vector A of the coil at any instant t is, Assuming when the coil was at rest, the angle between B and A was zero. As a result, the effective area of the coil exposed to the magnetic field lines changes with time, and thus, the flux at any time t is By Faraday’s law of electromagnetic induction, Thus,

e =N B A ω sin ωt

Considering the peak voltage E0 = B A ω,

e = e0 sin ωt

If the coil is of N turns the formula becomes,

e = N B A ω sin ωt

And the peak voltage becomes e0 = N B A ω

B) using the above formula,

e = N B A ω sin ωt

Where given data is,

B = 3.0 × 10-2 T

A = 200 × 10-4 m2

N = 20 turns, so,

e0 = N B A ω

E0 = 3.0 × 10-2 × 200 × 10-4 × 50 × 20 = 600000 × 10-6

E0 = 0.6 V

Let the resistance of the coil be R, so the peak current in the coil will be, OR

A) the diagram of a step-up transformer is given below Transformer uses the principle of mutual induction. A transformer consists of two sets of coils, insulated from each other. They are wound on a soft-iron core, either one on top of the other as shown in the diagram 1 or on separate limbs of the core as shown in the diagram 2. One of the coils called the primary coil has NP turns. The other coil is called the secondary coil; it has NS turns.

For a step-up transformer, NP < NS

Let the associated flux be , then induced voltage in secondary coil will be And the back emf generated in the primary coil is, But we know that, ep = vp, so, So, Also, in an ideal transformer there is no loss of power so,

iP vP = iS vS

So, B) using the above relation on the given data is,

vP = 2200 V,

NP = 3000 turns,

vs = 220 V

we get, Hence,

NS = 300 turns.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

The teachers of GPhysics - Board Papers

A. Draw a labeledPhysics - Board Papers

(a) In a series LPhysics - Board Papers

If a LC circuit iPhysics - Exemplar

If a LC circuit iPhysics - Exemplar

Electrical energyPhysics - Exemplar

Answer the followNCERT - Physics Part-I