Q. 54.0( 19 Votes )

# In Exercises 3 and 4, what is the net power absorbed by each circuit over a complete cycle. Explain your answer.

Answer :

In inductive circuit

Root mean square value of current, I = 15.92 A

Root mean square value of voltage, V = 220 V

The net power absorbed by each circuit over a complete cycle is given by the solution:

Power = VI cosФ

Where Ф is the phase difference between the voltage and current

For a pure inductive circuit, the phase difference between voltage and current in 90^{0}.

Substituting the above values, we get

⇒ P = 0

In capacitor circuit

Root mean square value of current, I = 2.49 A

Root mean square value of voltage, V = 110 V

The net power absorbed by each circuit over a complete cycle is given by the solution:

Power = VI cos Ф

For a pure capacitor circuit, the phase difference between voltage and current in 90^{0}.

Substituting the above values, we get

⇒ P = 0

∴ Zero power is absorbed by each circuit.

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