Q. 44.0( 26 Votes )

# A 60 μF capacitor is connected to a 110 V, 60 Hz A.C. supply. Determine the rms value of the current in the circuit.

Given: capacitance = 60 μF = 60 × 10-6 F

Voltage V = 110 V

Frequency f = 60 Hz

The diagram is:

Capacitive reactance is given by the following relation:

Xc = 1/ωC

Substituting ω = 2πv in the above formula, we get

Xc = 1/2πvC

Substituting the values, we get

Now, the root mean square value of the current can be calculated as follows:

Irms = V/Xc

Irms = 110V × 2 × 3.14 × (60Hz) × 60 × 10-6(F)

On calculating, we get

Irms = 2.49 A

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