Q. 54

The speed-time graph for a car is shown is Fig. 8.12.



(a) Find how far does the car travel in the first 4 seconds. Shade the area on the graph that represents the distance travelled by the car during the period.

(b) Which part of the graph represents uniform motion of the car?

Answer :


(a) Distance travelled by car in the 4 seconds


The area under the slope of the speed – time graph gives the distance travelled by an object.


In the given graph


56 full squares and 12 half squares come under the area slope for the time of 4 second.


Total number of squares = 56 + 12/2 = 62 squares


The total area of the squares will give the distance travelled by the car in 4 second.


On the time axis, 5 squares = 2s


1 square =25s=25s


On the speed asix 3 squares = 2 m/s


1 square =23m/s=23m/s


area of 1 square =25s×23m/s=415m=25s×23m/s=415m


area of 62 squares =415m×62=415m×62


24815m=16.53m24815m=16.53m


Therefore, car travels 16.53 m in first 4 second.


(b) Part MN of the slope of the graph is straight line parallel to the time axis, thus this potion of graph represents uniform motion of car.

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