# A cheetah starts from rest, and accelerates at 2 m/s2 for 10 seconds. Calculate :(a) the final velocity(b) the distance travelled.

Given:

a is the acceleration of the cheetah = 2m/s2

t is the time period for which cheetah is accelerating = 10 sec

u is the initial velocity of the cheetah  = 0 m/s

Formula used:

1. Final velocity "v"= u + a ×  t

where
v is the final velocity of the cheetah
u is the initial velocity of the cheetah
a is the acceleration of the cheetah
t is the time period

2. third equation of motion
v2 -u2=2×a×s
where,
v is the final velocity
u is the initial velocity
a is the acceleration of the body
s is the displacement

putting the value of u,a, t in the equation(1)

v=0+2×10=20 m/s

putting the value of v,a,s in equation(2)

400-0=2×2×s
s=100 m

The final velocity after 10 s will be 20 m/s and the displacement will be 100 m

=-Using the formula, we calculate distance travelled as 100m.

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