Q. 284.9( 9 Votes )

A cheetah starts from rest, and accelerates at 2 m/s2 for 10 seconds. Calculate :

(a) the final velocity

(b) the distance travelled.

Answer :

Given:

a is the acceleration of the cheetah = 2m/s2

t is the time period for which cheetah is accelerating = 10 sec

u is the initial velocity of the cheetah  = 0 m/s

Formula used:

1. Final velocity "v"= u + a ×  t 

where
v is the final velocity of the cheetah
u is the initial velocity of the cheetah
a is the acceleration of the cheetah
t is the time period

2. third equation of motion
 v2 -u2=2×a×s
where,
v is the final velocity
u is the initial velocity
a is the acceleration of the body
s is the displacement

putting the value of u,a, t in the equation(1)

v=0+2×10=20 m/s

putting the value of v,a,s in equation(2)

400-0=2×2×s
s=100 m

The final velocity after 10 s will be 20 m/s and the displacement will be 100 m









=-Using the formula, we calculate distance travelled as 100m.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
About Acceleration50 mins
Velocity Time GraphFREE Class
Champ Quiz | Motion under gravity46 mins
Third Equation of Motion36 mins
Learning Second Equation of motion41 mins
NCERT | Motion - Part 153 mins
Second Equation of Motion48 mins
Understanding Motion60 mins
Interactive Quiz - Motion29 mins
Learn The Use of Equations of Motion37 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :