Q. 284.9( 9 Votes )

# A cheetah starts from rest, and accelerates at 2 m/s^{2} for 10 seconds. Calculate :

(a) the final velocity

(b) the distance travelled.

Answer :

Given:

a is the acceleration of the cheetah = 2m/s^{2}

t is the time period for which cheetah is accelerating = 10 sec

u is the initial velocity of the cheetah = 0 m/s

Formula used:1. Final velocity "v"= u + a × t

where

v is the final velocity of the cheetah

u is the initial velocity of the cheetah

a is the acceleration of the cheetah

t is the time period

v

^{2}-u

^{2}=2×a×s

where,

v is the final velocity

u is the initial velocity

a is the acceleration of the body

s is the displacement

putting the value of u,a, t in the equation(1)

v=0+2×10=20 m/s

putting the value of v,a,s in equation(2)

400-0=2×2×s

s=100 m

The final velocity after 10 s will be 20 m/s and the displacement will be 100 m

=-Using the formula, we calculate distance travelled as 100m.

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