Q. 244.0( 20 Votes )

# A motorcycle moving with a speed of 5 m/s is subjected to an acceleration of 0.2 m/s^{2}. Calculate the speed of the motorcycle after 10 seconds, and the distance travelled in this time.

Answer :

According to the Question,

u = 5m/s

a = 0.2 m/s^{2}

v= ?

s=?

We know that **v= u+at**, Putting the values in the equation,we get:-

v= 5+(0.2)x10

∴ **v= 7 m/s**

We know that **v ^{2}-u^{2}= 2as**, Putting the values in the equation, we get:-

(7)

^{2}-(5)

^{2}= 2x(0.2)x s

49-25= 0.4s

∴

**s =**

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