Answer :

**Given:**

U = 20m/s

s = 50 m

V = o m/s

**formula used:**

using, Third equation of motion

v

^{2 }- u

^{2}=2×a×s

On applying the formula, we get

0-(20)^{2}=2 × a × 50

-400 =100× a

a= -4 m/s

^{2}

**Conlusion:**

The car has to decelerate at a rate of 4 m/s

The car has to decelerate at a rate of 4 m/s

^{2}Rate this question :

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