Q. 414.2( 13 Votes )

A bus increases its speed from 36 km/h to 72 km/h in 10 seconds. Its acceleration is :
A. 5 m/s2

B. 2 m/s2

C. 3.6 m/s2

D. 1 m/s2

Answer :

Given:
The initial velocity u =36 km/h=10 m/s
the Final velocity v =72 Km/h = 20 m/s
The time period t = 10 s
 
using first equation of motion
v – u = at
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time period 

putting the value  of v,u,t in the equation, we get

20 -10 =a ×10

a = 1 m/s2 






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