The price of 3 chairs and 2 tables is 4500 rupees and price of 5 chairs and 3 tables is 7000 rupees, then find the price of 2 chairs and 2 tables.

Let the price of one chair be 'x' and one table be 'y'.

Given,

Price of 3 chairs and 2 tables = 4500 Rs

3x + 2y = 4500

Multiplying by 3 both side,

9x + 6y = 13500

6y = 13500 - 9x eq.[1]

Price of 5 chairs and 3 tables = 7000 Rs

5x + 3y = 7000

Multiplying by eq.[2] both side,

10x + 6y = 14000

10x + 13500 - 9x = 14000 eq.[From 1]

x = 500

Putting this in eq.[1]

6y = 13500 - 9(500)

6y = 13500- 4500

6y = 9000

y = 1500

Also, Price of 2 chairs and 2 tables = 2x + 2y

= 2(500) + 2(1500)

= 1000 + 3000 = 4000 Rs.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Goprep Genius Quiz on Linear Equations34 mins
Smart Revision | Linear Equations in Two Variables34 mins
Interactive session on Linear Equations in Two Variables30 mins
NCERT | Imp. Qs. on Linear Equations in Two VariablesFREE Class
NCERT | Linear Equations41 mins
Bonus Questions on Linear Equations in Two Variables48 mins
Quiz | Testing Your Skills on Linear Equation in Two Variables36 mins
Quiz | Important Questions on Linear Equations In Two Variables49 mins
Champ Quiz | Do you Know about Linear Equations ?35 mins
Master Linear Equations40 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses