Q. 84.5( 41 Votes )
In ΔABC, the measure of angle A is equal to the sum of the measures of ∠B and ∠C. Also the ratio of measures of ∠B and ∠C is 4 : 5. Then find the measures of angles of the triangle.
Answer :
Given that, In ΔABC
∠A = ∠B + ∠C eq.[1]
Let ∠B = x and ∠C = y
Then,
∠A = x + y
In ΔABC, By angle sum property of triangle
∠A + ∠B + ∠C = 180°
⇒ x + y + x + y = 180
⇒ 2x + 2y = 180
⇒ x + y = 90
⇒ x = 90 - y eq.[2]
Also, Given that
⇒ 5x = 4y
From eq.[2]
⇒ 5(90 - y) = 4y
⇒ 450 - 5y = 4y
⇒ 9y = 450
⇒ y = 50°
Putting this in eq.[2]
⇒ x = 90 - 50 = 40°
Therefore, we have
∠A = x + y = 40° + 50° = 90°
∠B = x = 40°
∠C = y = 50°
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