Q. 14.1( 93 Votes )
In an envelope there are some 5 rupee notes and some 10 rupee notes. Total amount of these notes together is 350 rupees. Number of 5 rupee notes are less by 10 than number of 10 rupee notes. Then find the number of 5 rupee and 10 rupee notes.
Answer :
Let the number of 5 rupees notes = x
Let the number of 10 rupees notes = y
Given, Total amount is 350 Rupees
⇒ 5x + 10y = 350 eq.[1]
Also,
Number of 5 rupees notes are less by 10 than number of 10 rupees note,
y = x - 10⇒ x = y + 10 eq.[2]
Putting [2] in [1]
⇒ 5(y + 10) + 10y = 350
⇒ 5y + 50 + 10y = 350
⇒ 15y = 300
⇒ y = 20
Then, x = y + 10
⇒ x = 20 + 10
⇒ x = 30.
Answer: 30 notes of Rs 5 and 20 notes of Rs. 10.
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PREVIOUSSolve the following sets of simultaneous equations.i. x + y = 4; 2x - 5y = 1ii. 2x + y =5; 3x – y =5iii. 3x – 5y =16; x - 3y = 8iv. 2y – x =0; 10x + 15y =105v. 2x +3y + 4 = 0; x – 5y = 11vi. 2x – 7y =7; 3x + y =22NEXTThe denominator of a fraction is 1 more than twice its numerator. If 1 is added to numerator and denominator respectively, the ratio of numerator to denominator is1 : 2. Find the fraction.
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