Q. 74.3( 61 Votes )
The sum of the digits in a two-digits number is 9. The number obtained by interchanging the digits exceeds the original number by 27. Find the two-digit number.
Answer :
Let the unit digit be 'x'
Let the digit at ten's place be 'y'
The original number will be 10y + x
Given,
Sum of digits = 9
⇒ x + y = 9
⇒ x = 9 - y eq.[1]
Also,
If the digits are interchanged,
Reversed number will be = 10x + y
As, reversed number exceeds the original number by 27,
⇒ (10x + y) - (10y + x) = 27
⇒ 10x + y - 10y - x = 27
⇒ 9x - 9y = 27
⇒ x - y = 3
⇒ 9 - y - y = 3 eq.[using 1]
⇒ -2y = -6
⇒ y = 3
Using this in eq.[1]
⇒ x = 9 - 3 = 6
Hence the original number is 10y + x = 10(3) + 6 = 30 + 6 = 36.
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