The total number of lions and peacocks in a certain zoo is 50. The total number of their legs is 140. Then find the number of lions and peacocks in the zoo.

Let the number of lions be 'x' and peacocks be 'y'

Given, Total no of lions and peacocks is 50

x + y = 50

x = 50 - y eq.[1]

Also, Total no of their legs is 140, as lion has four legs and peacocks has 2 legs

4x + 2y = 140

4(50 - y) + 2y = 140

200 - 4y + 2y = 140

2y = 60

y = 30

Using this in eq.[1]

x = 50 - 30 = 20

Therefore,

No of lions, x = 20

No of peacocks, y = 30

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Goprep Genius Quiz on Linear Equations34 mins
Smart Revision | Linear Equations in Two Variables34 mins
Interactive session on Linear Equations in Two Variables30 mins
NCERT | Imp. Qs. on Linear Equations in Two VariablesFREE Class
NCERT | Linear Equations41 mins
Bonus Questions on Linear Equations in Two Variables48 mins
Quiz | Testing Your Skills on Linear Equation in Two Variables36 mins
NCERT | Imp Qs on Linear equation in Two Variables43 mins
Quiz | Important Questions on Linear Equations In Two Variables49 mins
Champ Quiz | Do you Know about Linear Equations ?35 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses