Answer :
Formula used:
Let the points A (1, 5) B (5, 8) and C (13, 14)
Distance of AB
⇒ AB = √ ((5 – 1)2 + (8 – 5)2)
⇒ AB = √ ((4)2 + (3)2)
⇒ AB = √ (16 + 9)
⇒ AB = √ 25
⇒ AB = 5
Distance of BC
⇒ BC = √ ((13 – 5)2 + (14 – 8)2)
⇒ BC = √ ((8)2 + (6)2)
⇒ BC = √ (64 + 36)
⇒ BC = √ 100
⇒ BC = 10
Distance of AC
⇒ AC = √ ((13 – 1)2 + (14 – 5)2)
⇒ AC = √ ((12)2 + (9)2)
⇒ AC = √ (144 + 81)
⇒ AC = √ 225
⇒ AC = 15
Now, we can see that AB + BC = AC.
∴ A, B and C are collinear. Hence, we cannot draw triangle using these coordinates.
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