Answer :
Let the speed of car at place A is x km/h and that of car at place B is y km/h
If they travel in same direction, they will meet after 7 hours, i.e. the difference of distance covered by them in 7 hours will be equal to distance b/w A and B.
As, distance = speed × time, and distance from A to B is 70 km
⇒ 7x - 7y = 70
⇒ x - y = 10
⇒ x = y + 10 eq.[1]
If they, travel in opposite direction, they will meet after 1 hour i.e. sum of distance travelled by both cars will be equal to the distance b/w A and B.
⇒ x + y = 70
Using eq.[1], we have
⇒ y + 10 + y = 70
⇒ 2y = 60
⇒ y = 30
Using this in eq.[1], we have
x = 30 + 10 = 40
Hence,
Speed of car at A = x = 40 km/h
Speed of car at B = y = 30 km/h
Rate this question :






















Write the correct
MHB - Math Part-IWrite the degree
MHB - Math Part-IWrite the followi
MHB - Math Part-ISubtract the seco
MHB - Math Part-IWrite the followi
MHB - Math Part-IWrite the index f
MHB - Math Part-IAdd the following
MHB - Math Part-IWrite the correct
MHB - Math Part-IWrite the correct
MHB - Math Part-IWrite the correct
MHB - Math Part-I