NCERT Solutions for Class 12 Physics Chapter 6 - Electromagnetic InductionShare
NCERT Physics Part 1 Solutions for Class 12th Chapter 6- Electromagnetic Induction prepared by a team of subject teachers in order to help them in their preparation for the exam. Understand the Chapter in an efficient and interesting way by using these NCERT Solutions which are drafted after considering the latest CBSE syllabus. These error-free NCERT Solutions are made available for the students at free of cost!
Chapter 6 introduces students with Introduction of Magnetism and Electricity together, Faraday’s Law, Lenz Law, Inductance, AC Generator, Eddy Currents, Magnetic Flux, Motional Electromotive Force, Energy Consideration and many such interesting topics. Refer to these guided Solutions for getting well-versed with the concepts of the topics and for solving the questions of the NCERT textbook.
NCERT Solutions for Class 12 Physics Chapter 6 - Electromagnetic Induction
A rectangular wire loop of sides 8 cm and 2 cm with a small cut is moving out of a region of uniform magnetic field of magnitude 0.3 T directed normal to the loop. What is the emf developed across the cut if the velocity of the loop is 1 cm s–1 in a direction normal to the (a) longer side, (b) shorter side of the loop? For how long does the induced voltage last in each case?
A 1.0 m long metallic rod is rotated with an angular frequency of 400 rad s–1 about an axis normal to the rod passing through its one end. The other end of the rod is in contact with a circular metallic ring. A constant and uniform magnetic field of 0.5 T parallel to the axis exists everywhere. Calculate the emf developed between the centre and the ring.
A circular coil of radius 8.0 cm and 20 turns is rotated about its vertical diameter with an angular speed of 50 rad s–1 in a uniform horizontal magnetic field of magnitude 3.0 × 10–2 T. Obtain the maximum and average emf induced in the coil. If the coil forms a closed loop of resistance 10 W, calculate the maximum value of current in the coil. Calculate the average power loss due to Joule heating.
Where does this power come from?
A horizontal straight wire 10 m long extending from east to west is falling with a speed of 5.0 m s–1, at right angles to the horizontal component of the earth’s magnetic field, 0.30 × 10–4 Wb m–2.
(a) What is the instantaneous value of the emf induced in the wire?
(b) What is the direction of the emf?
(c) Which end of the wire is at the higher electrical potential?
|Chapter 1 - Electric Charges and Fields|
|Chapter 2 - Electrostatic Potential and Capacitance|
|Chapter 3 - Current Electricity|
|Chapter 4 - Moving Charges and Magnetism|
|Chapter 5 - Magnetism and Matter|
|Chapter 6 - Electromagnetic Induction|
|Chapter 7 - Alternating Current|
|Chapter 8 - Electromagnetic Waves|