Answer :

Given:

Length of the wire, l = 10 m


Speed of wire, v = 5.0 ms - 1


Magnetic field B = 0.30 × 10–4 Wb m–2


The diagram is:



(a) The e.m.f induced in the wire can be calculated as follows:


e = Blv ...(1)


where B is the magnetic field


l is the length of the loop and,


v is the velocity of the rectangular loop


substituting the values in above equation, we get,


e = 0.30 × 10–4 Wb-m - 2 × 10 m × 5ms-1


e = 1.5 × 10–3 V


(b) The direction of the induced emf will be from west to east in accordance with the Fleming’s right - hand rule.


According to Fleming’s right - hand rule: When the right hand is held with the thumb, first finger and second finger mutually perpendicular to each other, as shown below.


Then, the thumb points in the direction in which the conductor moves; the first finger gives the direction of the magnetic field (N S); and the second finger gives the direction of the induced current.



(c) The east end of the straight wire will be having high electrical potential.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Find the current Physics - Exemplar

A metallic ring oPhysics - Exemplar

Find the current Physics - Exemplar

A rod of mass m aPhysics - Exemplar

A magnetic field Physics - Exemplar

A rectangular looPhysics - Exemplar

Consider an infinPhysics - Exemplar

ODBAC is a fixed Physics - Exemplar

A magnetic field Physics - Exemplar

A conducting wirePhysics - Exemplar