Q. 9
A pair of adjacent coils has a mutual inductance of 1.5 H. If the current in one coil changes from 0 to 20 A in 0.5 s, what is the change of flux linkage with the other coil?
Answer :
Given: Mutual conductance, μ = 1.5 H
Initial current I1= 0
Final current I2 = 20 A
Time taken t = 0.5 seconds
Change in the current can be calculated as:
dI = I1 - I2 = 20 – 0.0
dI = 20 A
The mutual conductance of the circuit is calculated using the formula:
or
As we know that
Substituting it in equation, we get
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PREVIOUSCurrent in a circuit falls from 5.0 A to 0.0 A in 0.1 s. If an average emf of 200 V induced, give an estimate of the self - inductance of the circuit.NEXTA jet plane is travelling towards west at a speed of 1800 km/h. What is the voltage difference developed between the ends of the having a span of 25 m, if the Earth’s magnetic field at the location has a magnitude of 5 × 10–4 T and the dip angle is 30°.
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