Answer :

Given: a = 7, n = 60 and l = a60 = 125


We know, an = a + (n – 1)d where a is first term or a1 and d is common difference and n is any natural number


When n = 60:


a60 = a + (60 – 1)d


a60 = a + 59d


When n = 32:


a32 = a + (32 – 1)d


a32 = a + 31d …………(i)


According to question:


a60 = 125


a + 59d = 125


7 + 59d = 125


59d = 125 – 7


59d = 118



d = 2


Now put the value of a = 7 and d = 2 in a32


a32 = a + 31d………(From (i))


a32 = 7 + 31(2)


a32 = 7 + 62


a32 = 69


Hence, 32thterm of the given A.P. is 69


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