# An A.P. consists

Given: a = 7, n = 60 and l = a60 = 125

We know, an = a + (n – 1)d where a is first term or a1 and d is common difference and n is any natural number

When n = 60:

a60 = a + (60 – 1)d

a60 = a + 59d

When n = 32:

a32 = a + (32 – 1)d

a32 = a + 31d …………(i)

According to question:

a60 = 125

a + 59d = 125

7 + 59d = 125

59d = 125 – 7

59d = 118 d = 2

Now put the value of a = 7 and d = 2 in a32

a32 = a + 31d………(From (i))

a32 = 7 + 31(2)

a32 = 7 + 62

a32 = 69

Hence, 32thterm of the given A.P. is 69

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