Q. 94.0( 2 Votes )

In a cricket tour

Answer :

Let the amount received by first place team be a Rs and d be difference in amount


As the difference is same hence the second-place team will receive a – d and the third place a – 2d and so on


The last team receives 275 rs


As there are 16 teams and all teams are given prizes hence the sequence will have 16 terms because there are 16 teams


a, a – d, a – 2d… ,275


The sequence is in AP with first term as a and common difference is ‘-d’


As the total prize given is of 8000rs hence


a + a – d + a – 2d … + 275 = 8000


The sum of n terms of AP is given by where


A is first term and d is common difference


There are 16 terms n = 16 and the sum Sn = 8000



8000 = 8(2a – 15d)


1000 = 2a – 15d …(i)


The last term of AP is 275 and nth term of AP is tn = a + (n – 1)d


The last term is tn = 275


275 = a + (16 – 1)(-d)


275 = a – 15d …(ii)


Subtract (ii) from (i) that is (i) – (ii)


1000 – 275 = 2a – 15d – a + 15d


725 = a


Hence amount received by first place team is 725 Rs.


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